Question

Equação exponencial:

Gente por favor me ajuda.

Answer 1

$\Large\boxed{\begin{array}{l}\sf64=4^3~~~~27=3^3\\\sf\dfrac{64}{27}=\dfrac{4^3}{3^3}=\bigg(\dfrac{4}{3}\bigg)^3\\\\\sf\bigg(\dfrac{27}{64}\bigg)^{x+3}=\bigg(\dfrac{3}{4}\bigg)^{3x-1}\\\\\sf\bigg[\bigg(\dfrac{4}{3}\bigg)^3\bigg]^{x+3}=\bigg[\bigg(\dfrac{4}{3}\bigg)^{-1}\bigg]^{3x-1}\\\\\sf\bigg(\dfrac{4}{3}\bigg)^{3x+9}=\bigg(\dfrac{4}{3}\bigg)^{-3x+1}\\\\\sf 3x+9=-3x+1\\\sf 3x+3x=1-9\\\sf 6x=-8\\\sf x=-\dfrac{8\div2}{6\div2}\\\\\sf x=-\dfrac{4}{3}\end{array}}$