Question

Equação exponencial 9x=1/27

Answer 1

$Resolu\c{c}\~ao \to \left\{\begin{array}{ccc}9^x = \frac{1}{27}\\\\(3^2)^x = \frac{1}{3^3}\\\\3^{2x} = 3^{-3}\\\\2x = -3\\\\\boxed{\boxed{x = -\frac{3}{2}}}\end{array}\right$

Espero ter ajudado. =^.^=