Question

equação exponencial 9 elevado a x+1=27 .

Answer 1

$9^{x+1}=27\\ \\ (3^2)^{x+1}=3^3\\ \\ 3^{2(x+1)=3^3$
$2(x+1)=3\\ \\ 2x+2=3\\ \\ 2x=1\\ \\ x=\frac{1}{2}$