equação exponencial
8^3x=3√32^x÷4^x-1
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Boa noite Pedrojoao
8^(3x) = ³√32^x/4^(x - 1)
8^(3x) = 32^(x/3)/4^(x - 1)
8^(3x) = 2^(5x/3)/2^(2x - 2)
8^(3x) = 2^(5x/3 - 2x + 2)
8^(3x) = 2^(2 - x/3)
2^(9x) = 2^(2 - x/3)
9x = 2 - x/3
27x = 6 - x
28x = 6
x = 6/28
x = 3/14
8^(3x) = ³√32^x/4^(x - 1)
8^(3x) = 32^(x/3)/4^(x - 1)
8^(3x) = 2^(5x/3)/2^(2x - 2)
8^(3x) = 2^(5x/3 - 2x + 2)
8^(3x) = 2^(2 - x/3)
2^(9x) = 2^(2 - x/3)
9x = 2 - x/3
27x = 6 - x
28x = 6
x = 6/28
x = 3/14
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