Question

equação exponencial 5^x2-2x=125 s={?}

Answer 1

5^x²-2x=125
5^x²-2x=5³
x²-2x=3
x²-2x-3=0
∆=b²-4ac
∆=(-2)²-4.1.(-3)
∆=4+12
∆=16
x=-b±√∆/2a
x=-(-2)-4/2.1
x=2-4/2
x=-2/2
x=-1
x=-(-2)+4/2.1
x=2+4/2
x=6/2
x=3
S={(-1, 3)}