Question

equacão exponencial 3^x-1 -3^x +3^x+1 +3^x+1=306

Answer 1

Resposta:

${3}^{x - 1} - {3}^{x} + {3}^{x + 1} + {3}^{x + 1} = 306 \\ \frac{ {3}^{x} }{3} - {3}^{x} + {3}^{x} .3 + {3}^{x} .3= 306 \\ {3}^{x} = y \\ \frac{y}{3} - y + 3y + 3y = 306 \\ \frac{y}{3} + 5y = 306 \\ y + 15y = 918 \\ 16y = 918 \\ y = \frac{918}{16} \\ y = \frac{459}{8} \\ {3}^{x} = \frac{459}{8} \\ x = log_{3}( \frac{459}{8} )$