Question

equação do segundo grau:x2-19x+88=0

Answer 1

Oi. Boa Tarde :)

Resposta:

Temos que:

$\setlength{\unitlength}{0.95cm}\begin{picture}(6,5)\put(0,0){\dashbox{0.1}(5,1){\\~~~\Large \tt x^2 - 19x + 88 = 0 ~~~\\}}\end{picture}$

Resolva por Bhaskara...

a = 1 /// b = -19 /// c = 88

Δ = b² - 4 . a . c

Δ = ( -19 )² - 4 . 1 . 88

Δ = 361 - 352

Δ = 9

x = -b ± √Δ /2 . a

x = - ( -19 ) ± √9 /2 . 1

x = 19 ± 3/2

x¹ = 19 + 3/ 2 = 22/ 2 = 11

x² = 19 - 3/ 2 = 16/2 = 8

$\setlength{\unitlength}{0.95cm}\begin{picture}(6,5)\put(0,0){\dashbox{0.2}(5,1){\\~~~\Large \tt S = (11, 8) \\}}\end{picture}$

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Bons Estudos!!!