Question

equação do segundo grau.

x2 + 10x – 600 =0

Answer 1

x²+10x-600=0
a=1  b=10  c=-600
Δ=b² - 4.a.c
Δ=(10)²-4.1.(-600)
Δ=100+2400=2500

x=-b+_√Δ ÷ 2
x=-10+_√2500 ÷ 2
x=-10+_50 ÷ 2

x,=-10+50 ÷ 2
x,=+40 ÷ 2
x,=20

x,,=-10-50 ÷ 2
x,,=-60 ÷ 2
x,,=-30