Question

equação do segundo grau 3x 2 -12x-36 = 0

Answer 1

Resposta:

3x² - 12x - 36 = 0

3(x² - 4x -12) = 0

3(x² - 4x -12) = 0

3(x² + 2x-6x - 12) =0

3 ( ( ² + 2 ) + ( − 6 − 1 2 ) ) = 0

3 ( ( + 2 ) − 6 ( + 2 ) ) = 0

3 ( ( + 2 ) − 6 ( + 2 ) ) = 0

x -6 = 0

x + 2 = 0

x = -2

x =6

x = 6

x = -2

Answer 2

Resposta:

3x²-12x -36= 0

3(x² -4x -12) = 0

3(x² -4x -12) = 0

x²  - 4x -12= 0

x= ⁻ᵇ ±√ᵇ² -4ac / 2a

x² - 4x -12=0

a=1

b= -4

c= -12

x= -(-4)±√(-4)² -4 . 1(-12) / 2 . 1

x = 4± √(-4)² -4 . 1(-12) / 2 .1

x= ± √16 -4 . 1(-12)/ 2 . 1

x= ± √16 -4 . 1(-12)/ 2 . 1

x= 4±√ 16 + 48/ 2 . 1

x= 4±√ 16 + 48/ 2 . 1

x= 4±√64/ 2 . 1

x= 4±√64/ 2 . 1

x= 4±8/ 2 . 1

x= 4±8/ 2 . 1

x= 4±8/ 2

x= 4±8/ 2

x= 4-8/ 2

x= 6

x= -2