Question

Equação do 2º grau


-x²+3x+10=0? Me ajudem a resolver

Answer 1

-x²+6x+10=0

Aplicar Bháskara
-b+-√b²-4ac
---------------- =
      2a
-6+-√6²-4x(-1)x10
----------------------- =
         2(-1)
-6+-√36+40
--------------- =
         -2
-6+-√76
---------- =
      -2
-6+-√2²x19
-------------- =
      -2
-6+-2√19
----------- =
       -2
x'=3+√19
x''=3-√19

Answer 2

Vc tem que fzr baskara
-x²+3x+10=0
Δ= 3² - 4(-1)(10)
Δ= 9 + 40
Δ=49
x1= -3 +√49/ 2(-1)
=-3+7/-2
=4/-2
=-2
x2= -3 -√49/ 2(-1)
= -3 -7/ -2
=-10/-2
= -5