Question

equação do 2°grau
5×2-3×-2=0

Answer 1

Resposta:

∆=b²-4ac

∆= (-3)²-4*5*(-2)

∆=9+40

∆= 49

x½= -b±√∆/2a

x½= 3±√49/2*5

x1= 3±7/10

x1= 3+7/10=1

x2= 3-7/10

x2=-4/10

x2=-2/5

obrigado