Question

equação do 2° grau
x² - 10x + 24 = 0​

Answer 1

$x^2-10x+24=0\\\\x_{1,\:2}=\frac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:24}}{2\cdot \:1}\\\\x_{1,\:2}=\frac{-\left(-10\right)\pm \:2}{2\cdot \:1}\\\\x_1=\frac{-\left(-10\right)+2}{2\cdot \:1},\:x_2=\frac{-\left(-10\right)-2}{2\cdot \:1}\\\\--\\\\=\frac{10+2}{2\cdot \:1}\\\\=\frac{12}{2\cdot \:1}\\\\=\frac{12}{2}\\\\=6\\\\--\\\\\frac{-\left(-10\right)-2}{2\cdot \:1}\\\\=\frac{10-2}{2\cdot \:1}\\\\=\frac{8}{2\cdot \:1}\\\\=\frac{8}{2}\\\\=4$

$As\:solucoes\:sao\\\\x=6,\:x=4$

Answer 2

Resposta:

X1 = 6 ; X2 = 4

Explicação passo a passo:

Primeiro vamos descobrir o valor de delta:

b² - 4ac = Δ

10² - 4 x 1 x 24 = 100 - 96 = 4

Δ = 4

Agora, aplicar a fórmula de Bhaskara:

-b +- √Δ / 2*a =

10 + √4 / 2*a = (10 + 2) / 2*1 = 12 / 2 =  X1 = 6

10 - √4 / 2*a = (10 - 2) / 2*1 = 8 / 2 =  X2 = 4