Equação do 2° grau: R = -1, -1/5
(2x+1)2 – 5(x+1)+4 =0
Simplifique expressão: R= -2m+ 2
(m-1)2 – (m+1) . (m-1)
arlansn:
a resposta bate
Soluções para a tarefa
Respondido por
2
Lembrando:
![(a+b)^{2}=a^{2}+2ab+b^{2}\\(a-b)^{2}=a^{2}-2ab+b^{2}\\(a+b)(a-b)=a^{2}-b^{2} (a+b)^{2}=a^{2}+2ab+b^{2}\\(a-b)^{2}=a^{2}-2ab+b^{2}\\(a+b)(a-b)=a^{2}-b^{2}](https://tex.z-dn.net/?f=%28a%2Bb%29%5E%7B2%7D%3Da%5E%7B2%7D%2B2ab%2Bb%5E%7B2%7D%5C%5C%28a-b%29%5E%7B2%7D%3Da%5E%7B2%7D-2ab%2Bb%5E%7B2%7D%5C%5C%28a%2Bb%29%28a-b%29%3Da%5E%7B2%7D-b%5E%7B2%7D)
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![(2x+1)^{2} - 5(x+1)+4=0\\([2x]^{2}+2*2x*1 + 1^{2})-5x-5+4=0\\4x^{2}+4x+1-5x-1=0\\4x^{2}-x=0\\x(4x-1)=0 (2x+1)^{2} - 5(x+1)+4=0\\([2x]^{2}+2*2x*1 + 1^{2})-5x-5+4=0\\4x^{2}+4x+1-5x-1=0\\4x^{2}-x=0\\x(4x-1)=0](https://tex.z-dn.net/?f=%282x%2B1%29%5E%7B2%7D+-+5%28x%2B1%29%2B4%3D0%5C%5C%28%5B2x%5D%5E%7B2%7D%2B2%2A2x%2A1+%2B+1%5E%7B2%7D%29-5x-5%2B4%3D0%5C%5C4x%5E%7B2%7D%2B4x%2B1-5x-1%3D0%5C%5C4x%5E%7B2%7D-x%3D0%5C%5Cx%284x-1%29%3D0)
Igualando ambos a zero:
![x=0\\\\4x-1=0\\4x=1\\x=1/4\\\\S=\{0,\frac{1}{4}\} x=0\\\\4x-1=0\\4x=1\\x=1/4\\\\S=\{0,\frac{1}{4}\}](https://tex.z-dn.net/?f=x%3D0%5C%5C%5C%5C4x-1%3D0%5C%5C4x%3D1%5C%5Cx%3D1%2F4%5C%5C%5C%5CS%3D%5C%7B0%2C%5Cfrac%7B1%7D%7B4%7D%5C%7D)
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![(m - 1)^{2} - (m + 1)(m - 1)\\(m^{2} - 2*m*1 + 1^{2}) - (m^{2} - 1^{2})\\m^{2}-2m+1-(m^{2}-1)\\m^{2}-2m+1-m^{2}+1\\-2m+2 (m - 1)^{2} - (m + 1)(m - 1)\\(m^{2} - 2*m*1 + 1^{2}) - (m^{2} - 1^{2})\\m^{2}-2m+1-(m^{2}-1)\\m^{2}-2m+1-m^{2}+1\\-2m+2](https://tex.z-dn.net/?f=%28m+-+1%29%5E%7B2%7D+-+%28m+%2B+1%29%28m+-+1%29%5C%5C%28m%5E%7B2%7D+-+2%2Am%2A1+%2B+1%5E%7B2%7D%29+-+%28m%5E%7B2%7D+-+1%5E%7B2%7D%29%5C%5Cm%5E%7B2%7D-2m%2B1-%28m%5E%7B2%7D-1%29%5C%5Cm%5E%7B2%7D-2m%2B1-m%5E%7B2%7D%2B1%5C%5C-2m%2B2)
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Igualando ambos a zero:
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