Question

Equação do 2 grau fórmula de bhaskara
4ײ-16=0.

Answer 1

$\large \boxed{ \begin{array}{l} 4x {}^{2} - 16 = 0 \\ \\ a = 4 \\ b = 0 \\ c = - 16 \\ \\ ∆ = b {}^{2} - 4ac \\ ∆ = 0 {}^{2} - 4.4.( - 16) \\ ∆ = 0 + 256 \\ ∆ = 256 \\ \\ x = \dfrac{ -b \pm \sqrt{∆} }{2a} \\ \\ x = \dfrac{ \sqrt{256} }{2.4} \\ \\ x = \dfrac{16}{8} \\ \\ x = 2 \end{array}}$