Question

Equação do 2 grau
4x(elevado a 2)-12x+8=0

Answer 1

$4x^{2} -12x+8=0$

Δ = b²-4ac

Δ = -12² - 4.4.8

Δ = 144 - 128

Δ = 16

Fómula de Bhaskara:

$x=\frac{-b+-\sqrt{delta}}{2a} \\ \\ x=\frac{12+-\sqrt{16}}{2.4} \\ \\ x=\frac{12+-4}{8} \\ \\ x'=\frac{12+4}{8} =\frac{16}{8} =2\\ \\ x''=\frac{12-4}{8} =\frac{8}{8} =1\\ \\ S=(x'=2;~~x''=1)$

Answer 2

4x² - 12x  + 8 = 0

Δ = b² -  4ac

a = 4

b =-12

c =8

Δ = (-12)² - 4*4*8

Δ = 144 - 128

Δ = 16

x = -b +-√Δ /2a

x = -(-12) +- √16 /2*4

x = 12 +-4 /8

x' = 12+4 /8

x' = 16/8

x' = 2

x" = 12-4 /8

x" = 8/8

x" = 1

S = {1  e 2}