Question

Equação de segundo grau 2°​

Answer 1

Resposta:

a) x' = -2 e x'' = -5

b) x' = 0 e x'' = -2

c) x' = 5 e x'' = 2

d) x' = 0 e x'' = -4

e) delta negativo, não há raiz real

f) x' = -1 e x'' = -1

Explicação passo-a-passo:

a) -x²+7x-10=0

a = -1 b = 7 c = -10

Δ = 7² - 4 . (-1) . (-10)

Δ = 49 - 40

Δ = 9

x = -7+-$\sqrt{9$ / 2.(-1)

x = -7+-3/-2

x' = -7+3/-2 = -4/-2 = -2

x'' = -7-3/-2 = -10/-2 = -5

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b) x²+2x=0

a = 1 b = 2 c = 0

Δ = 2² - 4 . 1 . 0

Δ = 4 - 0

Δ = 4

x = -2+-$\sqrt{4\\}$/2.1

x = -2+-2/2

x' = -2+2/2 = 0/2 = 0

x'' = -2-2/2 = -4/2 = -2

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c) x²-7x+10=0

a = 1 b = -7 c = 10

Δ = (-7)² - 4 . 1 . 10

Δ = 49 - 40

Δ = 9

x = -(-7)+-$\sqrt{9\\}$/2.1

x = 7+-3/2

x' = 7+3/2 = 10/2 = 5

x'' = 7-3/2 = 4/2 = 2

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d)-x²+4 = 0

a = -1 b = 4 c = 0

Δ = 4² - 4 . (-1) . 0

Δ = 16 + 0

Δ = 16

x = -4+-$\sqrt{16\\}$/2.(-1)

x = -4+-4/-2

x' = -4+4/-2 = 0/-2 = 0

x'' = -4-4/-2 = -8/-2 = -4

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e) 2x²-3x+4=0

a = 2 b = -3 c = 4

Δ = (-3)² - 4 . 2 . 4

Δ = 9 - 32

Δ = -23

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f) x²+2x+1 = 0

a = 1 b = 2 c = 1

Δ = 2² - 4 . 1 . 1

Δ = 4 - 4

Δ = 0

x = -2 +-$\sqrt{0}$/2.1

x = -2+-0/2

x' = -2+0/2 = -2/2 = -1

x'' = -2-0/2 = -2/2 = -1