Question

equação de 2º grau

9x²+2x-8=0

Answer 1

${9x}^{2} + 2x - 8 = 0$

∆ = 2² - 4.9.(-8)

∆ = 4 + 288

∆ = 292

$x = \frac{ - 2 + - \sqrt{292} }{2 \times 9}$

$x = \frac{ - 2 + - 2 \sqrt{73} }{18}$

$x = \frac{ - 2 + 2 \sqrt{73} }{18} \\ x = \frac{ - 2 - 2 \sqrt{73} }{18}$

$x = \frac{ - 1 + \sqrt{73} }{9} \\ x = \frac{ - 1 - \sqrt{73} }{9}$