Question

Equação de 2°grau formula de Bhaskara x²+8x+15=0

Answer 1

Faça o delta: Δ = b2 - 4.a.c 
Δ=8²-4.1.15
Δ=64 - 4. 1 . 15 
Δ=4

Resolva: x = (-b +- √Δ)/2a
x'' = (-8 - √4)/2.1
x' = -6 / 2 = x' = -3
x'' = -10 / 2 = x'' = -5

Resultado: 
x= -3
x= -5

Answer 2

$x^2 + 8x + 15 =0 \\ \\ a = 1 \\ b = 8 \\ c = 15 \\ \\ \Delta = b^2 -4 .a . c \\ \Delta = 8^2 -4 \times 1 \times 15 \\ \Delta = 64 - 60 \\ \Delta = 4 \\ \\ \frac{-b +- \sqrt{delta} }{2} \\ \\ \frac{-8 +- \sqrt{4} }{2} \\ \\ \frac{-8 +- 2}{2} \\ \\ x' = \frac{-8 + 2 }{2} \\ \\ x' = \frac{-6 }{2} \\ \\ \boxed{x' = -3} \\ \\ x" = \frac{-8 - 2}{2} \\ \\ x" = \frac{-10}{2} \\ \\ \boxed{x" = -5} \\ \\ \boxed{\bf{ Resposta : S = (-5 , -3)}}$