Question

Equação de 2 grau
x2-9x+14=0

Answer 1

$x^{2} - 9x + 14$
$Bhaskara -\ \textgreater \ \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$
$Delta = (b)^{2} - 4.(a).(c)$
$Delta = (9)^{2} - 4.(1).(14)$
$Delta = 81 - 4.14$
$Delta = 81 - 56$
$Delta = 25$

$x1 = \frac{-(-9) + \sqrt{25} }{2} = \frac{14}{2} = 7$
$x2 = \frac{-(-9) - \sqrt{25} }{2} = \frac{4}{2} = 2$

S = {2,7}

x = 2 ou x = 7

Espero ter ajudado ^-^