Question

equaçao de 2 grau (x+3)²=1

Answer 1

Resposta:

Explicação passo-a-passo:

(x+3)²=1

x²+6x+9=1

x²+6x+8=0

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}+6x+8=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=6~e~c=8\\\\\Delta=(b)^{2}-4(a)(c)=(6)^{2}-4(1)(8)=36-(32)=4\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(6)-\sqrt{4}}{2(1)}=\frac{-6-2}{2}=\frac{-8}{2}=-4\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(6)+\sqrt{4}}{2(1)}=\frac{-6+2}{2}=\frac{-4}{2}=-2\\\\S=\{-4,~-2\}$

Outro jeito de resolver:

(x+3)²=1

(x+3)=±√1=±1

Para x+3=1 => x= 1-3= -2

Para x+3= -1 => x= -1-3= -4