Question

Equação biquadrada x4-4x2+3=0

Answer 1

${x}^{4} + {4x}^{2} + 3 = 0 \\ {x }^{2} = y \\ {y}^{2} + 4y + 3 = 0 \\ y = \frac{ 4 + - \sqrt{4} }{2} \\ y1 = \frac{ 4 + 2}{2} = 3 \\ y2 = \frac{ 4 - 2}{2} = 1 \\ {x}^{2} = 3 \\ {x}^{2} = 1$

$s = - 1. - \sqrt{3} .1. \sqrt{3}$