Question

equação biquadrada x4 – 17 x2 + 16 =0

Answer 1

$x^{4} - 17 x^{2} +16=0$

$x^{2} =y$

$y^{2} -17 y^{} +16=0$

Δ=289-64
Δ=225
√Δ=15

$y'= \frac{17+15}{2} = \frac{32}{2} =16$

$y"= \frac{17-15}{2} = \frac{2}{2} =1$

como x²=y
p/ y=16
x²=16
x=$\sqrt{16}$
x'=4
x"=-4

p/y=1
x²=1
x=√1
x'=1
x"=-1

S={-4,-1,1,4}