Question

Equação Biquadrada me ajudeeeem!!!!!!!!!!!

X ^ 4 - 1 3 x ^ 2 +36=0

Answer 1

$x^4-13x^2+36=0\\\\Considerando : x^2=y\\\\y^2-13y+36=0\\\Delta=-13^2-4\cdot1\cdot36\\\Delta=25\\\\y=\frac{13\pm5}{2}\\\\y'=9\\y''=4\\\\Substituindo y :\\x^2=y\to x=\pm \sqrt{y}\\\\x'= \pm \sqrt{9}\to x'=\pm 3\\x''= \pm \sqrt{4}\to x''=\pm 2\\\\s=(-3,-2,2,3)$