Question

equação (4+2c)^2-16=0​

Answer 1

$\large\boxed{\begin{array}{l}\rm(4+2c)^2-16=0\\\rm (4+2c)^2=16\\\rm 4+2c=\pm\sqrt{16}\\\rm 4+2c=\pm4\\\rm 4+2c=4\\\rm2c=4-4\\\rm 2c=0\\\rm c=\dfrac{0}{2}\\\rm c=0\\\rm 4+2c=-4\\\rm 2c=-4-4\\\rm 2c=-8\\\rm c=-\dfrac{8}{2}\\\\\rm c=-4\\\rm S=\{-4,0\}\end{array}}$