Question

equação 2 grau com bhaskara 12x^2+17x+6=0

Answer 1

12x²+17x+6=0

a=12; b=17; c=6

Δ=b²-4.a.c
Δ=(17)²-4.(12).(6)
Δ=289-288
Δ=1

x=(-b±√Δ)/2.a
x=(-(17)±√1)/2.(12)
x=(-17±1)/2.(12)
x¹=(-17+1)/2.(12)=-16/24=-8/12=-4/6=-2/3
x²=(-17-1)/2.(12)=-18/24=-9/12=-3/4