Question

equação 2^2x+1 =32 o valor de x e: a)1 b)2 c)3 d)4 e)5

Answer 1

Basta igualar as bases, eliminá-las, e resolver a equação dos expoentes:

$2^{2x+1 }=32\to\\\\ \not2^{2x+1 }=\not2^5\to\\\\ 2x+1=5\to\\\\ 2x=5-1\to\\\\ 2x=4\to\\\\ x= \dfrac{4}{2} \to\\\\ \large\boxed{x=2}$

Answer 2

$2^{2x+1} =32 \\ \\ 2^{2x+1} =2^5 \\ \\ 2x+1=5 \\ \\ 2x=5-1 \\ \\ 2x=4 \\ \\ x= \frac{4}{2} \\ \\ x=2$