Question

eq. de 2 grau ( utilizando a formula de baskara )
2$x^{2}$-8x+8=0

Answer 1

Vamos lá :

2x² - 8x + 8 = 0 ÷ 2

x² - 4x + 4 = 0

a = 1 ; b = - 4 ; c = 4

Δ = b² - 4ac
Δ = (-4)² - 4.1.4
Δ = 16 - 16
Δ = 0        ⇒√Δ = 0

Aplica a formula de Bhaskara :

x = - b +/- √Δ / 2a
x = - (- 4) +/- 0 / 2.1
x = 4 +/- 0 / 2

x' = 4 + 0/2 = 4/2 = 2
x'' = 4 - 0/2 = 4/2 = 2

S = {2}

Espero ter ajudado !!!