Question

enterpolando-se 17 meios aritmeticos entre 117 e 333

Answer 1

a1 = 117

a19 = 333

a19 = a1 + 18r

333 = 117 + 18r

333 - 117 = 18r

216 = 18r

216/18 = r

12 = r

pa(117, 129, 141,153,165,177,189,201,213,225,237,249,261,273,285,297,309,321,333)