Question

enocntre o x ( angulos 32 e 12 ) medida de 10 ​

Answer 1

tg32°=0,62

tg12°=0,21

$\tan(32) = \frac{x}{y} \\ x = y \tan(32) \\ x = 0,62y$

$\tan(12) = \frac{x}{10 + y} \\ 0,21 = \frac{0,62y}{10 + y} \\ 2,1 + 0,21y = 0,62y$

$0,62y - 0,21y = 2,1 \\ 0,41y = 2,1 \\ y = \frac{2,1}{0,41} \\ y = 5,12$

$x = 0,62y \\ x = 0,62.5,12\\ x= 3,17$