Question

encontrei os zeros da funcao f(x)=x²+6×+5

Answer 1

f(0) = x²+6x+5
x²+6x+5=0
a= 1 b=6 c=5
∆=b²-4ac
∆= 6²-4.1.5
∆= 36-20
∆=16
x= -b±√∆ / 2a
x= -6 ± 4 /2
x'= -6+4/2 = -2/2 = -1
x''= -6-4/2 = -10/2= -5