Question

Encontrei a razão da PG(64, 16, 4, ...).

Answer 1

$> resolucao \\ \\ \geqslant \: razao \: da \: pg \: (64 \: . \: 16 \: . \: 4....) \\ \\ q = \frac{a2}{a1} \\ \\ q = \frac{16 \div 4}{64 \div 4} \\ \\ q = \frac{1}{4} \\ \\ \\ \\ = = = = = = = = = = = = \\ \\ \\ \\ q = \frac{a3}{a2} \ \\ \\ \ q = \frac{4 \div 4}{16 \div 4} \ \\ \\ \ q = \frac{1}{4} \\ \\ \\ \\ > < > < > < > < > < > <$