Question

Encontre x' e x'' x²+6x+8=0​

Answer 1

$x^2 + 6x + 8 = 0\\\\a = 1\\b = 6\\c = 8\\\\\Delta = b^2 - 4ac\\\Delta = 6^2 - 4 \cdot 1 \cdot 8\\\Delta = 36 - 32\\\Delta = 4\\\\x = \dfrac{-b\pm\sqrt\Delta}{2a} = \dfrac{-6\pm\sqrt{4}}{2\cdot1} = \dfrac{-6\pm2}{2}\\\\x' = \dfrac{-6+2}{2} = \dfrac{-4}{2} = -2\\\\x" = \dfrac{-6-2}{2} = \dfrac{-8}{2} = -4\\\\\boxed{S= \{-4, -2\}}$

x' = -2 e x" = -4