Question

Encontre x' e x'' x²+6x+8=0​

Answer 1

$\large\boxed{\begin{array}{lr} {x}^{2} + 6x + 8 = 0 \\ \\ a = 1 \\ b = 6 \\ c = 8 \\ \\ ∆ = b {}^{2} - 4.a.c \\ ∆ = 6 {}^{2} - 4.1.8 \\ ∆ = 36 - 32 \\∆ = 4 \\ \\ x = \frac{ - b \pm \sqrt{∆} }{2.a} \\ \\ x = \frac{ - 6 \pm \sqrt{4} }{2.1} \\ \\ x = \frac{ - 6 \pm2}{2} \\ \\ x ' = \frac{ - 6 + 2}{2} = \frac{ - 4}{2} = - 2\\ \\ x" = \frac{ - 6 - 2}{2} = \frac{ - 8}{2} = - 4 \end{array}}$