Question

Encontre uma equação quadrática com a=3 e raízes x1 = -2 e x2 = 7

Answer 1

Resposta:

Resposta:a) 3 e 7

×'=3×"=7

(×-×')(×-×")=0

(×-3)(×-7)=0

×2-7×-3×+21=0

×2-10×+21=0

b) 5 e 0

×'=5

×"=0

(×-×')(×-×")=0

(×-5)(×-0)=0

×2-0×-5×+0=0

×2-5×+0=0

×2-5×=0

c)5 é 0

×'=5

×"=0

(×-×')(×-×")=0

(×-5)(×-0)=0

×2-0×-5×+0=0

×2 -5×+0=0

×2-5×=0

d) - 3 e 6

×'=-3

×"=6

(×-×')(×-×")=0

(×-(-3))(×-6)=0

(×+3)(×-6)=0

×2-6×+3×-18=0

×2-3×-18=0

e) -3 é 0

×'=-3

×"=0

(×-×')(×-×")=0

(×-(3))(×-0)=0 Olha o sinal

(×+3)(×-0)=0

×2-0×+3×-0=0

×2 +3×-0=0

×2+3×=0