Question

Encontre os valores de x:

a) x²- 8x+12=0
b) 4x²-20=0

Answer 1

x² - 8x +12=0

a=1

b=-8

c=12

Delta -> b² -4ac

(-8)² - 4.1.12

64 - 48

Delta é igual á 16

x= -b+- (mais ou menos) √delta/2a

x= 8 +- √16/2.1

x= 8+- 4/2

x'= 8 + 4/2 -> x' = 12/2 -> x'= 6

x''= 8-4/2 -> x''= 4/2 -> x''= 2