Question

encontre os valores abc
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Answer 1

Resposta:

cos(2π/3) = cos(120) = -1/2

sen(4π/3) = sen(240) = -√3/2

sen(2π/3) = sen(120) = √3/2

cos(4π/3) = cos(240) = -1/2

A = (1/2 + √3/2)/(√3/2 + 1/2) = 1

sen(7π/4) = sen(315) = -√2/2

cos(5π/4) = cos(225) = -√2/2

cos(3π/4) = cos(135) = -√2/2

sen(3π/4) = sen(135) = √2/2

B = (-√2/2 -√2/2)/(-√2/2 -√2/2) = 1