Question

Encontre os quatro primeiros termos:an=n3-n2,,an=3-n,,an=n2,,an=n2-(n-1)

Answer 1

$a_n=n^3-n^2 \\ a_1=1^3-1^2=1-1=0 \\ a_2=2^3-2^2=8-4=4\\a_3=3^3-3^2=27-9=18\\a_4=4^3-4^2=64-16=48.\\ \\ a_n=3-n \\ a_1=3-1=2 \\ a_2=3-2=1 \\ a_3=3-3=0 \\ a_4=3-4=-1\\\\ a_n=n^2 \\ a_1=1^2=1 \\ a_2=2^2=4 \\ a_3=3^2=9 \\ a_4=4^2=16\\\\ a_n=n^2-(n-1)=n^2-n+1\\a_1=1^2-1+1=1\\a_2=2^2-2+1=4-2+1=3\\a_3=3^2-3+1=9-3+1=7\\a_4=4^2-4+1=16-4+1=13$