Question

Encontre os coeficientes das equações e as resolvas. 3x²+4x+1=0 *

S={-1/3 -1}

S={1 2}

S={2 4}

S={2/3 3/5}

NENHUMAS DAS RESPOSTAS​

Answer 1

$3x^2+4x+1=0\Longrightarrow a=3,\ b=4,\ c=1.$

$\boxed{x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}}\Longrightarrow x=\dfrac{-4\pm2}{6}=\dfrac{-2\pm1}{3}$

$\Longrightarrow x=-1\ \text{ou}\ x=-\dfrac{1}{3}\Longrightarrow \boxed{x=\left\{-1,-\dfrac{1}{3}\right\}}$

Answer 2

Resposta: S={-1/3 -1}

Explicação passo a passo:

3x²+4x+1=0

a=3

b=4

c=1

x= -b ± √b² - 4·a·c

___________

2·a

x= -4 ± √4² - 4·3·1

___________

2·3

x= -4 ± √16 - 12

_________

6

x= -4 ± √4

_________

6

x= -4 ± 2

_________

6

x'= -4-2 = -6 = -1

___ __

6 6

x''= -4+2 = -2 = -1

___ _ _

6 6 3

S: {-1, -1/3}