Question

Encontre o valor numérico de uma equação a) 9x+5=4x b) 20=-6x+32 c) 7x+1-5x=9

Answer 1

a) 9x+5=4x
9x - 4x = - 5
5x = 5
x = 5 / 5
x = 1


b) 20=-6x+32
6x = 32 - 20
6x = 12
x = 12 / 6
x = 2



c) 7x+1-5x=9
7x - 5x = 9 - 1
2x = 8
x = 8 / 2
x = 4

Answer 2

Olá!

$a) \: 9x + 5 = 4x \\ 9x - 4x = - 5 \\ 5x = - 5 \\ x = - \frac{5}{5} \\ x = - 1$

$b) \: 20 = - 6x + 32 \\ 6x = 32 - 20 \\ 6x = 12 \\ x = \frac{12}{6} \\ x = 2$

$c) \: 7x + 1 - 5x = 9 \\ 2x = 9 - 1 \\ 2x = 8 \\ x = \frac{8}{2} \\ x = 4$