Question

encontre o valor de y nas proporções

Answer 1

e) $\frac{y+3}{y-2} = \frac{3}{2}$
3(y-2)=2(y+3)
3y-6=2y+6
3y-2y=6+6
y=12

f) $\frac{2}{1} = \frac{15-y}{y}$
15-y=2y15=2y+y
3y=15
y=15/3
y=5

g)$\frac{20}{y+1} = \frac{16}{y}$
20y=16(y+1)
20y=16y+16
20y-16y=16
4y-16
y=16/4
y=4

h)$\frac{3}{2} = \frac{y+3}{y-1}$
3(y-1)=2(y+3)
3y-3=2y+6
3y-2y=6+3
y=9
espero ter ajudado