Question

Encontre o valor de x nas figuras abaixo utilizando o Teorema de Pitágoras.

Answer 1

Resposta:

${x}^{2} = {8}^{2} + {6}^{2} \\ {x}^{2} = 64 + 36 \\ {x}^{2} = 100 \\ x = \sqrt{100} \\ x = 10$

${10}^{2} = {x}^{2} + {6}^{2} \\ 100 = {x}^{2} + 36 \\ 100 - {x}^{2} - 36 = 0 \\ - {x}^{2} + 64 = 0 \\ - {x}^{2} = - 64 \times ( - 1) \\ {x}^{2} = 64 \\ x = \sqrt{64} \\ x = 8$

Answer 2

$\large \boxed{ \begin{array}{l} x {}^{2} = 8 {}^{2} + 6 {}^{2} \\ x {}^{2} = 64 + 36 \\ x {}^{2} \: = \: 100 \\ x = \sqrt{100} \\ x = 10 \end{array}}$

$\large\boxed{ \begin{array}{l}10 {}^{2} = 6 {}^{2} + x {}^{2} \\ 100 = 36 + x {}^{2} \\ 100 - 36 = x {}^{2} \\ 64 \: = \: x {}^{2} \\ x = \sqrt{64} \\ x = 8\end{array}}$