Question

encontre o valor de X na equação: 4x + 2= 5x + 8.​

Answer 1

$\boxed{\begin{array}{l}\underline{\rm 1^a\,forma\,de\,resolver:}\\\sf 4x+2=5x+8\\\sf usando\,o\,princ\acute ipio\,aditivo~subtraia~5x\,nos\,dois\,membros.\\\sf 4x-\underline{5x}+2=5x-\underline{5x}+8\\\sf -x+2=8\\\sf usando\,o\,princ\acute ipio\,aditivo,subtraia\,2\,nos\,dois\,membros.\\\sf -x+2-\underline{2}=8-\underline{2}\end{array}}$

$\boxed{\begin{array}{l}\sf -x=6\\\sf usando\,o\,princ\acute ipio\,multiplicativo\\\sf multiplique\,os\,dois\,membros\,por\,-1\\\sf -x\cdot\underline{(-1)}=6\cdot\underline{(-1)}\\\\\sf x=-6\\\sf S=\{-6\}\end{array}}$

$\boxed{\begin{array}{l}\underline{\rm 2^a\,forma\,de\,resolver:}\\\sf 4x+2=5x+8\\\sf procuremos\,deixar\,letras\,e\,n\acute umeros\,com\,letras\\\sf no\,membro\,esquerdo\,desfazendo\\\sf a\,operac_{\!\!,}\tilde ao\,matem\acute atica\,sempre\,que\,mudar\,de\,membro.\\\\\sf Analogamente\,deixemos\,os\,n\acute umeros\,no\,membro\,direito\\\sf desfazendo\,a\,operac_{\!\!,}\tilde ao\,ao\,mudar\,de\,membro.\end{array}}$

$\boxed{\begin{array}{l}\sf4x+2=5x+8\\\sf 4x-5x=8-2\\\sf -x=6\cdot(-1)\\\sf x=-6\end{array}}$

Answer 2

$\Large\displaystyle\begin{gathered} \sf{ 4x+2=5x+8} \end{gathered}$

$\Large\displaystyle\begin{gathered} \sf{ 4x-5x=8-2 } \end{gathered}$

$\Large\displaystyle\begin{gathered} \sf{ -x=6\cdot(-1) } \end{gathered}$

$\Large\displaystyle\text{ \begin{gathered}\boxed{\boxed{ \sf{ x=-6 }} } \end{gathered} }$