Question

encontre o conjunto solução de cada equação​

Answer 1

Resposta:

Explicação passo a passo:

$a)$

$x^{2} -4=0$

$x^{2} =4$

$x=+\sqrt{4} =>x=+2$

$x=-\sqrt{4} =>x=-2$

$S=(+2;-2)$

$b)$

$x^{2} -36=0$

$x^{2} =36$

$x=+\sqrt{36} =>x=+6$

$x=-\sqrt{36} =>x=-6$

$S=(+6;-6)$

$c)$

$x^{2} -100=0$

$x^{2} =100$

$x=+\sqrt{100}=>x=+10$

$x=-\sqrt{100}=>x=-10$

$S=(+10;-10)$

$d)$

$x^{2} -64=0$

$x^{2} =64$

$x=+\sqrt{64}=>x=+8$

$x=-\sqrt{64}=>x=-8$

$S=(+8;-8)$

$e)$

$x^{2} +81=0$

$x^{2} =-81$

$x=\sqrt{-81}$

S = {  }

$f)$

$2x^{2} -50=0$

$2x^{2} =50$

$x^{2} =50/2$

$x^{2} =25$

$x=+\sqrt{25} =>x=+5$

$x=-\sqrt{25}=>x=-5$

$S=(+5;-5)$

$g)$

$3x^{2} -192=0$

$3x^{2} =192$

$x^{2} =192/3$

$x^{2} =64$

$x=+\sqrt{64}=>x=+8$

$x=-\sqrt{64}=>x=-8$

$S=(+8;-8)$

$h)$

$x^{2} -121=0$

$x^{2} =121$

$x=+\sqrt{121} =>x=+11$

$x=-\sqrt{121}=>x=-11$

$S=(+11;-11)$

$i)$

$-2x^{2} +288=0$

$2x^{2} =288$

$x^{2} =288/2$

$x^{2} =144$

$x=+\sqrt{144} =>x=+12$

$x=-\sqrt{144}=>x=-12$

$S=(+12;-12)$