Question

encontre o 101* termo da p.a (-4, 1, 6...)

Answer 1

$\mathtt{R = A_3 - A_2} \\ \mathtt{R = 6 - 1} \\ \mathtt{R = 5} \\ \\ \mathtt{A_n = a_1 + (n - 1)~.~R} \\ \mathtt{A_{101} = -4 + (101-1)~.~5} \\ \mathtt{A_{101} = -4 + 100~.~5} \\ \mathtt{A_{101}=-4 +500} \\ \mathtt{A_{101} = 496}$


Resposta: 496