Question

encontre as raizes de (x+3).(x+3)=0 e de (x+4)2=16

Answer 1

Resposta:

Explicação passo-a-passo:

1-

(x+3)(x+3)= 0

x²+3x+3x+9=0

x²+6x+9=0

x=-b+-√b²-4ac/2a

x'=-6+√6²-4.1.9/2.1

x'=-6+√36-36/2

x'=-6+0/2

x'=-6/2 = -3

x"=-6-√0/2

x"=-6/2 = -3

2-

(x+4)2=16

2x+8=16

2x=16-8

2x=8

x=8/2

x=4