Question

Encontre as raízes das equações.

a) 6.(1-x) + (x-2) = 3.(4-x)
b) (x+1)² - (2x+3) . (x+4) = 11.(x-1)

Answer 1

$A) 6.(1-x) + (x-2) = 3.(4-x) \\ 6 -6x +x -2 = 12 -3x \\ -6x +x +3x = 12 -6 +2 \\ -2x = +8 .(-1) \\ 2x = -8 \\ x = -8 / 2 \\ x = -4$


$(x+1) ^{2} - (2x+3) . (x+4) = 11.(x-1) \\ ( x^{2} +2.x.1+ 1^{2} ) -( 2x^{2} +8x +3x +12) = 11x -11 \\ x^{2} +2x + 1 -2x^{2} -11x -12 =11x -11 \\ -2x^{2} +x^{2} +2x-11x-11x +1-12 +11 = 0 \\ x^2 -20x = 0 \\ x ( x -20) = 0 \\ x' +- 0 \\ x" +- 20$