Question

encontre as raizes da equacao x²-4x-5=0

Answer 1

x= (-b±√∆)/2a
∆= b²-4ac
= (-4)²-4*1*(-5)
=16+20
=36

x=(-(-4)±√36)/2*1
x=(4±6)/2
x'=(4+6)/2 = 10/2 = 5
x"=(4-6)/2 = -2/2 = -1

Answer 2

$x^2-4x-5=0 \\ \\ \Delta=(-4)^2-4.1.(-5) \\ \Delta=16+20 \\ \Delta=36 \\ \\ x= \frac{-b+- \sqrt{36} }{2} \\ \\ x'= \frac{4+6}{2}= 5 \\ \\ x''= \frac{4-6}{2}=-1 \\ \boxed{S={5~e~ -1}}$

Espero ter ajudado