Question

Encontre as raízes da equação x2 + 11x + 24

Answer 1

Resposta:

As raízes de f(x) são -8 e -3.

Explicação passo-a-passo:

Para encontrar as raízes da equação faça f(x)=x²+11x+24=0.

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}+11x+24=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=11~e~c=24\\\\\Delta=(b)^{2}-4(a)(c)=(11)^{2}-4(1)(24)=121-(96)=25\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(11)-\sqrt{25}}{2(1)}=\frac{-11-5}{2}=\frac{-16}{2}=-8\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(11)+\sqrt{25}}{2(1)}=\frac{-11+5}{2}=\frac{-6}{2}=-3\\\\S=\{-8,~-3\}$

Answer 2

Resposta:

X1 = - 3 e X2 = - 8

Explicação passo-a-passo:

x2 + 11x + 24 = 0

∆ = b2 - 4ac

∆ = 11^2 - 4• 1 • 24

∆ = = 121 - 96

∆ = 25

X1 = ( - 11 + √25 ) / 2

X1 = ( - 11 + 5 ) / 2

X1 = - 6/2

X1 = - 3

X2 = ( - 11 - √25 ) / 2

X2 = ( - 11 - 5 ) / 2

X2 = - 16 / 2

X2 = - 8