Question

Encontre as raizes da equação x²+11+24=0

Answer 1

x²+11x+24=0

∆ = 11² - 96 = 25

x = -11±√25/2

x' = -11+5/2 = -3

x'' = -11-5/2 = -8

Answer 2

$\textsf{Leia abaixo}$

Explicação passo-a-passo:

$\large\boxed{\begin{array}{l} \rm \: x {}^{2} + 11x + 24 = 0 \\ \\ \Rightarrow \begin{cases} \rm \: a = 1 \\ \rm \: b = 11 \\ \rm \: c = 24\end{cases} \\ \\ \rm\Delta = b {}^{2} - 4ac \\ \Delta = 11 {}^{2} - 4 \: . \: 1 \: . \: 24 \\\Delta = 121 - 96 \\ \Delta = 25 \\ \\ \rm \: x = \dfrac{ - b \pm \sqrt{\Delta} }{2a} \\ \\ \rm \: x = \dfrac{ - 11 \pm \sqrt{25} }{2 \: . \: 1} \\ \\ \rm \:x = \dfrac{ - 11 \pm5}{2} \begin{cases} \rm{x_1 = \dfrac{ - 11 + 5}{2} = \dfrac{ - 6}{2} = \boxed{ - 3}} \\ \\ \rm{x_2 = \dfrac{ - 11 - 5}{2} = \dfrac{ - 16}{2} = \boxed{ - 8 } }\end{cases}\end{array}}$