Question

encontre as raizes da equação

 

2x²+ 12x + 16 = 0

Answer 1

$2x^2+ 12x + 16 = 0 \\ \\ x^2+6x+8 =0 \\ \\ \Delta=6^2-4.1.8 =36-34=4 \\ \\ x=\frac{-6+-\sqrt4}{2}=\frac{-6+-2}{2}=-3+-1 \\ \\ x_1=-4 \\ \\ x_2=-2$

Answer 2

$2x^{2} +12+16=0= \Delta= b^{2} -4.a.c= \Delta= 12^{2} -4.2.16= \Delta=144-128=16  x^{1} =-+12=\sqrt{16} /2.2=-12-4/4=-16/4=-4 x^{2} =-+12 \sqrt{16} /2.2=+12-4/4=8/4=2$


S{-4,2}